Question

If x^2 +y^2 =3 and x-y = 3 ( value of x^3 - y^3 )

Answer 1

Answer:

The answer is 0

Step-by-step explanation:

Given $x-y=3$ and $x^2+y^2=3$

Using

$(x-y)^2=x^2+y^2-2xy\\\Rightarrow 9=3-2xy\\\Rightarrow 2xy=3-9\\\Rightarrow 2xy=-6\Rightarrowxy=-3$

Therefore

$x^3-y^3=(x-y)(x^2+y^2+xy)=3(3-3)=0$