Question

if x^2 - y^2 = 31
find the integral value of X and Y​

Answer 1

Answer:

Given

∣

∣

∣

∣

∣

∣

∣

∣

x

2

0

3

x

2

1

1

1

4

∣

∣

∣

∣

∣

∣

∣

∣

=28

Expanding determinant on both sides.

⇒x

2

(8−1)−x(0−3)+1(0−6)=28

⇒7x

2

+3x−6−28=0

⇒7x

2

+3x−34=0

∴x=2

Step-by-step explanation:

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