Question

if x^2 - y^2 = 31 find the integral value of X and Y​

Answer 1

Given :-

x²-y² = 31

To find :-

The integral values of X and Y.

Solution :-

Given that x²-y² = 31

It can be written as

(x+y)(x-y) = 31×1

On comparing both sides then

x+y = 31 -------(1)

x-y = 1 ---------(2)

(+)

____________

2x+0 = 32

____________

=> 2x = 32

=> x = 32/2

=> x = 16

Therefore, x = 16

On Substituting the value of x in (1)

=> 16+y = 31

=>y = 31-16

=> y = 15

Therefore, y = 15

Answer :-

The integral values of x and y are 16 and 15 respectively.

Used formulae:-

• (a+b)(a-b) = a²-b²

Answer 2

(24)^2- (27)^2 =31

24×24= 576

27×27= 729

729-576= 163