Question

If x^2+y^2=32 and xy=2,find the value of x-y

Answer 1

Answer:

use the identity-

(a-b)²=a²+b²+2ab

(x-y)²=x²-2xy+y²

(x-y)²= 32 -2(2)

(x-y)²=32-4

x-y=√28

x-y=2√7

Simple!

Hope it helps!

Answer 2

Answer:

Given x2+y2= 32

xy= 2

using formula (x-y)2

(x-y)2 = x2 +y2-2xy

(x-y)2= 32 - 2×2

(x-y)2= 28

x-y= √28= 2√7