Question

if x^2+y^2=36xy then find the value of 2log(x-y) ​

Answer 1

Step-by-step explanation:

x²+y²=36xy

Apply log on both sides

logx²+logy²=log36xy

2logx+2logy=log36+logx+logy

logx+logy=log36

logxy=log36

xy=36

therefore x=6,y=6

Then2(log(x-y)) is

2(log(6-6))

2(log0)

2(1)

=2. log0=1