Math, asked by aasthasuthar, 9 months ago

If x^2+y^2=37 and xy=6 find i)x+y ii)x-y iii)x^2-y^2

Answers

Answered by praniji76
7

Answer:

Step-by-step explanation:

(X+Y)^2=X^2+Y^2+2XY

            =37+2(6)=49

⇒X+Y=√49

          =7

∴X+Y=7

(X-Y)^2=X^2+Y^2-2XY

⇒(x-Y)^2=37-12=25

⇒X-Y=5

X^2-Y^2=(x+Y)(X-y)

⇒7*5=35

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