If x^2+y^2=4 and (x-y)^2=2 then xy=?
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Answer:
xy=3
Step-by-step explanation:
x^2+y^2=4 eq.1
(x-y)^2=2
using identity
x^2+y^2-2xy=2
substituting eq.1
4-2xy=2
xy=3
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