Math, asked by ha294137, 9 months ago

If x^2+y^2=4 and (x-y)^2=2 then xy=?​

Answers

Answered by gangulisujata123
0

Answer:

xy=3

Step-by-step explanation:

x^2+y^2=4    eq.1

(x-y)^2=2

using identity

x^2+y^2-2xy=2

substituting eq.1

4-2xy=2

xy=3

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