if x^2+y^2=49 and x-y=3.find the value of x^3-y^3
Answers
Answered by
15
x^3 - y^3 = (x-y) ( x^2 + y^2 +xy)
we need xy
(x-y)^2 = x^2 + y^2 - 2xy
9 = 49 - 2xy
xy = 20
x^3 - y^3 = (x-y) ( x^2 + y^2 +xy) = 3 ( 49 - 20) = 2 (29) = 87
we need xy
(x-y)^2 = x^2 + y^2 - 2xy
9 = 49 - 2xy
xy = 20
x^3 - y^3 = (x-y) ( x^2 + y^2 +xy) = 3 ( 49 - 20) = 2 (29) = 87
Anonymous:
mark as brainliest
Answered by
25
Similar questions