if x^2 + y^2 = 5, then how much is xy ?
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Step-by-step explanation:
x+y=3
x=3-y
putting the value of x
in this
x²+y²=5
(3-y) ²+y²=5
9-6y+y²+y²=5
2y²-6y+9-5=0
2y²-6y+4=0
2y²-4y-2y+4=0
2y(y-2)-2(y-2)=0
(2y-2) (y-2) =0
2y-2=0 or y-2=0
y=1 or y=2
so x=2 or 1
so x×y=2×1 or 1×2=2
I HOPE THIS WILL HELP.......
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