Math, asked by soniyakuril9464, 1 year ago

If x^2+y^2=53 and xy = 14 .find the value of x^3 + y^3

Answers

Answered by preeti9578
9

Answer:

Step-by-step explanation:

x²+y²=53

xy=14

we know that,

(x+y)²=x²+y²+2xy

(x+y)²=53+2*14

(x+y)²=53+28

(x+y)²=81

(x+y)=√81

(x+y)=9

now,

(x+y)³=x³+y³+3xy(x+y)

x³+y³=(x+y)³-3xy(x+y)

x³+y³=(9)³-3*14*9

        =729-378

        =351

HOPE IT HELPS

MARK AS BRAINLIEST

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