If x^2+y^2=53 and xy = 14 .find the value of x^3 + y^3
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Answer:
Step-by-step explanation:
x²+y²=53
xy=14
we know that,
(x+y)²=x²+y²+2xy
(x+y)²=53+2*14
(x+y)²=53+28
(x+y)²=81
(x+y)=√81
(x+y)=9
now,
(x+y)³=x³+y³+3xy(x+y)
x³+y³=(x+y)³-3xy(x+y)
x³+y³=(9)³-3*14*9
=729-378
=351
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