Question

If x^2+y^2=58 and x-y=10 .find the value of x^3 -y^3?

Answer 1

x³-y³=370.....
Hope it may help you

Answer 2

Answer:

$x^3-y^3 =370$

Step-by-step explanation:

Given: $x^2+y^2=58$

           $x-y=10$

To find: $x^3 -y^3$

Solution:

$x-y=10$

Squaring both sides

$(x-y)^2=(10)^2$          

$x^2+y^2 -2xy = 100$    

Since we are given that $x^2+y^2=58$

So, $58 -2xy = 100$    

$xy=-21$    

Now $x^3-y^3 =(x-y)(x^2+xy+y^2)$

Substitute the values :

$x^3-y^3 =(10)(58-21)$

$x^3-y^3 =370$