Math, asked by sayamsingla3110, 11 months ago

If x^2-y^2=58 and x-y=4 then find value of x and y

Answers

Answered by shadowsabers03
0

Answer:

x = 9.25

y = 5.25

Step-by-step explanation:

x² - y² = 58

(x + y)(x - y) = 58

(x + y)4 = 58

x + y = 58 / 4

x + y = 14.5

(x + y) + (x - y) = 14.5 + 4

x + y + x - y = 18.5

2x = 18.5

x = 9.25

(x + y) - (x - y) = 14.5 - 4

x + y - x + y = 10.5

2y = 10.5

y = 5.25

Hope this helps. ^_^

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