Math, asked by ravi1954p, 4 days ago

If x^2+Y^2=58 and xy =21 find x-y

Answers

Answered by Gorika2101

0

Answer:

(x-y)²=x²+y²-2xy

putting values

(x-y)²= 58-2×21

(x-y)²=58-42=16

x-y=√16=±4

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