Question

. If x^2 + y^2 = 65 and xy = 28, find (i) x + y (ii) x - y.​

Answer 1

Step-by-step explanation:

(x+y)^2=(x+y)^2+2xy

(x+y)^2=65+56

(x+y)^2=121

x+y=11

ans we know

(x-y)^2=x^2+y^2-2xy

(x-y)^2=65-56

x-y=3

Answer 2

Answer:

Step-by-step explanation:

x^2 + y^2 = 65 and xy = 28

(x + y)^2 =  x^2 + y^2 + 2xy

              =     65    +   2*28

               =   65   +  56

(x + y)^2   =   121

(x + y) =  11

(x - y)^2 = x^2 + y^2 - 2xy

             =   65    -   2*28

              =  65    -   56

    (x - y)^2    =   9

 (x - y) = 3