Question

if x^2+y^2=6xy,prove that 2 log (X+y)=log X +log y +3 log 2​

Answer 1

Answer:

x²+y²=6xy

add 2xy on both sides

x²+y²+2xy=8xy

(x+y)²=8xy

apply log on both sides

log(x+y)²=logx+logy+log8

2log(x+y)=logx+logy+3log2