Question

If x^2+y^2=9 and xy=4, then the value of (x+y)^2 is ____________.

Answer 1

Answer:

x²+y²=9

xy=4

(X+y)²= x²+y²+2xy

(x+y)²= 9+4

=13

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Answer 2

Answer:

(x + y)² = 17

Step-by-step explanation:

Given:

• x² + y² = 9

• xy = 4

To find:

• (x + y)²

Method to find:

We can derive our answer with the use of algebraic identities.

(x + y)² = x² + 2xy + y²

(The first algebraic identity)

Substituting the values,

9 + (2 * 4)

⇒ 9 + 8

⇒ 17

Other algebraic identities:

• (a - b)² = a² - 2ab + b²

• (a + b)(a - b) = a² - b²

• (x + a)(x + b) = x² + (a + b)x + ab

Hope it helps!