Math, asked by kabeerraheela, 3 months ago

if x^2+y^2/ x^2-y^2 +2 1/8 then find x:y and x^3+y^3/x^3-y^3

Answers

Answered by ava4495
6

Answer:

3x-2y=24 _____ (1)

2x-3y=18 _____ (2)

multiply (1) by 2

6x - 4y = 48

multiply (2) by 3

6x-9y=54

subtracting

6x - 4y = 48

6x - 9y = 54

-     +    -

___________

5y = -6

y=−5−6

3x−2(−56)=24

=3x+512=24

=3x=24−512=5120−12=5108

∴x=536

x+y=536−6=530=6

x−y=536+6=542

Answered by randhiraditya084
0

Hope it will help you......

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