Question

If x^2+y^2+xy=1,x+y =2 then xy=

Answer 1

Please see the attachment

Answer 2

$x {}^{2} + y {}^{2} + xy = 1 \: and \: x + y = 2 \\ \\ hey \: mate \: here \: is \: your \: answer \: may \: it \: helps \: you \\: \\ \\ x { }^{2} + {y}^{2} + xy + xy = 1 + xy \\ {x}^{2} + {y}^{2} + 2xy = 1 + xy \\ (x + y) {}^{2} = 1 + xy \\ {(2)}^{2} = 1 + xy \\ 4 - 1 = xy \\ 3 = xy \\ therefore \: xy = 3$