Math, asked by aishdeep2, 1 year ago

if x^2+y^2 +z^2=15 xy+yz+zx=33 then find the value of x+y+z

Answers

Answered by kishank229p0xrx8
1
as (x+y+z)²=x²+y²+z²+2xy+2zx+2yz
put value of x²+y²+z²
 (x+y+z)²=15+2(xy+yz+zx)                                           (take comon 2)
 (x+y+z)²=15+2*33
 (x+y+z)²=81
 (x+y+z)=9


plz make it brainalist
Answered by pulkitraina260ovri2y
1
please mark brainliest
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