Question

If (x^2)+(y^2)+(z^2)=24 and xy+yz+zx =20 Find x+y+z

Answer 1

Answer:

(x+y+z)² = x²+y²+z²+2(xy+yz+zx)

=> (x+y+z)² = 24+2(20)

=> (x+y+z)² = 64

=> (x+y+z) = 8

Answer 2

Answer:

x+y+z=8

Step-by-step explanation:

(x+y+z)^2= x^2+y^2+z^2+2xy+2yz+2zx

= 24+2×20

=64

√64=8