Question

if x^2+y^2+z^2=28 ,x+y+z=6 then xy+yz+zx is equal to?

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

x^2+y^2+z^2=28 ,x+y+z=6 then xy+yz+zx is equal to =4

Step-by-step explanation:

we know The expanded form of (x+y+z)² =x² +y²+z²+2xy+2yz+2zx

               (x+y+z)² =x² +y²+z²+2(xy+yz+zx)

given x^2+y^2+z^2=28 ,

x+y+z=6

substituting the values in above equation

(x+y+z)² =x² +y²+z²+2(xy+yz+zx)

(6)²=28+2(xy+yz+zx)

2(xy+yz+zx)=36-28

(xy+yz+zx)=8/2

xy+yz+zx =4

x^2+y^2+z^2=28 ,x+y+z=6 then xy+yz+zx is equal to =4