Question

if x^2+y^2+z^2=29 and xy+yz+zx=26 then the value of x+y+z is?​

Answer 1

Answer:

x ² + y² + z² = 29

xy + yz + zx = 26

x³ + y³ + z³ - 3xyz = 0

(x+y+z) ( x² + y² + z² -xy - yz -xz) = 0

(x + y + z ) {(x² + y² + z² - ( Xy + yz + xz)} = 0

( x + y + z) { (29) - ( 26) } = 0

x + y + z = 26 - 29 = -3

therefore,, X + y + z = -3

Answer 2

Answer:

here is your answer