Question

if x^2+y^2+z^2=34 and xy-yz-zx=33 find the value of x+y+z​

Answer 1

x²+y²+z²=34

or, (x+y+z)²-2(xy+yz+zx) =34

or, (x+y+z)²-2×33=34

or, (x+y+z)²=34+66

or, (x+y+z)=(10²)½

or, x+y+z=10

So, we get the value of , (x+y+z) is 10

I hope it is helpful for you.