Question

If x^2 + y^2 + z^2 - xy - yz - zx = 0 then the value of (x+y)/z is
(A) 2
(B) 1
(C) xy
(D) yz​

Answer 1

Answer:

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Answer 2

Answer:

Option(A)

Step-by-step explanation:

Given Equation is :

x² + y² + z² - xy - yz - zx = 0

Multiply by '2', we get

2x² + 2y² + 2z² - 2xy - 2yz - 2zx = 0

⇒ x² + y² - 2xy + y² + z² - 2yz + x² + z² - 2zx = 0

⇒ (x - y)² + (y - z)² + (z - x)² = 0

⇒ x = y = z

Thus,

(x + y)/z

⇒ (x + x)/x

⇒ (2x)/x

⇒ 2

Hope it helps!