If x=2 y=3 find the value k of the linear equation 28x-8y+k=0
Answers
Answered by
1
28(2)-8(3)+k=0
56-24+k=0
k = - 32
56-24+k=0
k = - 32
Answered by
2
Hey there!
As, x = 2 and y = 3
Now put there value in 28x-8y+k=0
28(2) - 8(3) + k = 0
56 - 24 + k = 0
32 + k = 0
k = - 32
Hope it help
As, x = 2 and y = 3
Now put there value in 28x-8y+k=0
28(2) - 8(3) + k = 0
56 - 24 + k = 0
32 + k = 0
k = - 32
Hope it help
goyalvikas78:
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