If x = 2 , y = 3 is the solution of the equations 3x+ay =12 and bx + 3y = 19 find a+b.
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x=2, y=3.
3x+ay=12 and bx+3y=19, a+b= ?
3(2)+a(3)=12, b(2)+3(3)=19
6+3a=12, 2b+9=19
3a=12-6, 2b=19-9
3a=6, 2b=10
a=6/3, b=10/2
a=2, b=5.
a+b= 2+5= 7 .
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