Question

If x=2, y = 3,z=-1, find the value of x3+y3+z3+3xyz​

Answer 1

Answer:

Given:

x² + y² + z² = 83

And

x + y + z = 15

To Find :

The value of , x³ + y³ + z³ - 3 x y z

Solution :

∵ ( x + y + z )² = x² + y² + z² + 2 ( x y + y z + z x )

And

x + y + z = 15

So, 83 + 2 ( x y + y z + z x ) = ( 15 )²

Or, 2 ( x y + y z + z x ) = 225 - 83

Or, 2 ( x y + y z + z x ) = 142

∴ ( x y + y z + z x ) = \dfrac{142}{2}

2

142

i.e ( x y + y z + z x ) = 71

Again:

∵ x³ + y³ + z³ - 3 x y z = ( x + y + z ) [ ( x² + y² + z² ) - ( x y + y z + z x ) ]

Or, = ( 15 ) × [ 83 - 71 ]

Or, = 15 × 12

i.e = 180

Hence, The value of x³ + y³ + z³ - 3 x y z is 180 . Answer

Step-by-step explanation:

Hope it helps you..

Thanksgiving..

Answer 2

Answer:

= (2)3 + (3)3 + (1)3 + 3 *2*3*1

= 6 + 9 + 3 + 18

= 18 + 18

= 36

hope it helps you