If (x-2)+(y-3)+(z-4)=0, then the value of xyz
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(x-2)+(y-3)+(z-4)=0
Step-by-step explanation:
- (x-2=0)
- x=2
- (y-3=0)
- y=3
- (z-4=0)
- z=4
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Answered by
2
Step-by-step explanation:
x=-2 or y=3 or z=-4
x=-2 or y=3 or z=-4Therefore xyz should be a multiple of -2 or 3 or -4 or 0
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