Question

If x=-2,y=6 is the solution of 3ax+2by=6 then find the value of b from 2(a-1)+2(3b-4)=4

Answer 1

$<b > hey here is your answer$

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Equation = 3ax + 2by = 6
Where x = (-2)
and
Y = 6

Putting the value of x and y in equation

3a × (-2) + 2b × 6 = 6
= -6a + 12b = 6
= -a + 2b = 1.
= 2b = 1+a
= b = (1+a)/2. -(1)

In equation 2
2(a-1)+2(3b-4) = 4

Putting b = (1+a)/2 in equation

= 2(a-1) + 2[3(1+a)/2 -4] = 4
= 2a - 2 + 3 + 3a - 8 = 4
= 5a -7 = 4
= 5a = 4+7 = 11
= a = 11/5

b = (1+a)/2
= (1+11/5)/2
= 16/(5×2)
= 16/10
= 8/5 answer

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Hope this helps you

Answer 2

X = -2 and Y = 6





3aX + 2bY = 6 -------(1)


Substitute the value of X and Y in equation (1) , we get :



3 × a × (-2) + 2 × b × 6 = 6



-6a + 12b = 6




-6a + 12b - 6 = 0



6 ( -a + 2b - 1 ) = 0



-a + 2b = 1



a = ( 2b - 1 ) -------(2)



Putting the value of a in ,


2 ( a - 1 ) + 2 ( 3b - 4 ) = 4



2 ( 2b - 1 - 1 ) + 2 ( 3b - 4 ) = 4



2 ( 2b - 2 ) + 2 ( 3b - 4 ) = 4




4b - 4 + 6b - 8 = 4



4b + 6b - 4 - 8 = 4


10b - 12 = 4


10b = 4+12


10b = 16


b = 16/10

b = 8/5