if x=2-y then show that x^3+6xy +y^3-8=0
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x=2-y
or, x+y=2
cubing both sides,
x³+y³+3xy(x+y)=8
or, x³+y³+3xy(2)=8
or, x³+y³+6xy=8
or, x³+6xy+y³-8=0 (proved)
or, x+y=2
cubing both sides,
x³+y³+3xy(x+y)=8
or, x³+y³+3xy(2)=8
or, x³+y³+6xy=8
or, x³+6xy+y³-8=0 (proved)
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