Question

if x=2-y,then show thatx^3+6xy+y^3-8=0

Answer 1

If x = 2 - y

Then ,

x³ + 6xy + y³ - 8 = 0

( 2 - y )³ + 6 ( 2 - y ) y + y³ - 8 = 0

-y³ + 6y² - 12y + 8 - 6y² + 12y + y³ - 8 = 0

0 = 0

Answer 2

Answer is in the attached document.....