Question

if x =(20-4t^2) find average velocity between t=0and t=2sec​

Answer 1

Answer:

The average velocity is 8 unit per sec

Explanation:

Given

• The Distance x = 20 - 4t²  unit
• Change in time Δt = ( 2 - 0 ) s = 2 s

Let's assume the velocity = V unit/s

so,  V = $\sf{\dfrac{\partial (20 - 4t^{2})}{\partial }}$

Or, V =  - 8t       unit/s

Now velocity at t = 0

• V1 = - 8 × 0 =  0  unit/s

• And   velocity  at t = 2 sec

• V2 =  - 8 × 2 = - 16

So, Average velocity =$\sf{\dfrac{v2 - v1}{2} = \dfrac{- 16 - 0}{2}}$

• | v |= 8   unit/sec

Hence The average velocity is 8 unit per sec

Answer 2

Answer:

Hence The average velocity is 8 unit per sec

Explanation:

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