Question

If x = 222, y = 223, z = 225 then the value of x3 + y3 + z3 - 3xyz is

Answer 1

x3+y3+z3−3xyz=12(x+y+z) [(x−y)2+(y−z)2+(z−x)2]

=12(222+223+225) [(222−223)2+(223−225)2+(225−222)2]

=12(670)[1+4+9]

= 12×670×14=4690

PLZ MARK AS BRAINLIEST!^_^