If x=2³×3×5 and y=2²×3³ then HCF (X, Y) is
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First, we have to find the values of x and y.
x =
2³ × 3 × 5
2³ = 2 × 2 × 2 = 8
8 × 3 × 5 = 120
∴ x = 120
y =
2² × 3³
2² = 2 × 2 = 4
3³= 3 × 3 × 3 = 27
4 × 27 = 108
∴ y = 108
Now, we have to find the HCF of 120 and 108.
(I have attached an image for the HCF.)
∴ The HCF for 108 and 120 is 20.
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