If x√25^(x+1\4).√5.5^-x/5.√5^-x = P, then find the value of P.
Answers
Step-by-step explanation:
Answer:
F1(t) is the cubic function;
F2(t) is the exponential function;
F3(t) is the quadratic function.
Here are some observations which lead to these conclusions.
All power functions ktp with p 0 are zero for t = 0. Thus F2 cannot be a power function.
Assuming that F1(t) = ktn with n = 2 or n = 3, we can evaluate F1(1) to obtain k. In this case, k = 2.5.
Since F1(t) = (2.5)tn with n = 2 or n = 3, we can figure out n by evaluating at t = 1.2.
(2.5)(1.2)2 = 3.6 and (2.5)(1.2)3 = 4.32,
so n = 3.
Return to Exercises
Question: Solve 3 x2.2 = 6.
Answer: x = 21/(2.2). Since 2.2 = 22/10 = 11/5, this is the same as x = 25/11.
Question: 3 x2.2 = -6.
Answer: x = (-2)1/(2.2). Since 2.2 = 22/10 = 11/5, this is the same as x = (-2)5/11 which is a well-defined real number. On the other hand, your calculator or computer algebra package will probably treat the exponent 1/(2.2) as a REAL number and, not caring that this is a rational number with an odd denominator, will feel that (-2)1/(2.2) is a complex number which is NOT real. You be the judge!