if x=2a+1 and y=a-1 is a solution of the equation 2x-3y+5=0, then find the value of a........plzzz answer quick
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Ans.
2x - 3y + 5 = 0
or, 2(2a + 1) -3(a-1) + 5 = 0
or, 4a + 2 - 3a + 3 + 5 = 0
or, a = -10
I HOPE THAT THIS HELPS YOU.
2x - 3y + 5 = 0
or, 2(2a + 1) -3(a-1) + 5 = 0
or, 4a + 2 - 3a + 3 + 5 = 0
or, a = -10
I HOPE THAT THIS HELPS YOU.
arpitakhare2003:
thanks
Answered by
17
x = 2a + 1
y = a - 1
2x - 3y + 5 = 0
substituting values of x and y:
2(2a + 1) - 3(a - 1) + 5 = 0
4a + 2 - 3a + 3 + 5 = 0
a + 10 = 0
a = -10
verification:
x = -19, y = -11
2x - 3y + 5 = 2(-19) - 3(-11) + 5
= -38 + 33 + 5
= -38 + 38
= 0
y = a - 1
2x - 3y + 5 = 0
substituting values of x and y:
2(2a + 1) - 3(a - 1) + 5 = 0
4a + 2 - 3a + 3 + 5 = 0
a + 10 = 0
a = -10
verification:
x = -19, y = -11
2x - 3y + 5 = 2(-19) - 3(-11) + 5
= -38 + 33 + 5
= -38 + 38
= 0
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