If x= 2a-1, y=(2a – 2) and z =3-4a, then the value of x3 + y2 + z’ will be :
Answers
Answered by
1
Answer:
Hello
As given x=(2a−1)y=(2a−2)z=(3−4a)
then the value of x
3
+y
3
+z
3
⇒(2a−1)
3
+(2a−2)
3
+(3−4a)
3
∵(x−y)
3
=x
3
−y
3
−3x
2
y+3xy
2
⇒(2a−1)
3
+(2a−2)
3
+(3−4a)
3
⇒(8a
3
−1−12a
2
+6a)+(8a
3
−8−24a
2
+24a)+(27−64a
3
−108a+144a
2
)
⇒48a
3
+18+108a
2
−78a⇒18−78a+108a
2
+48a
3
⇒6(3−13a+18a
2
+8a
3
)
Answered by
0
Answer:
6a-3+4a-4+3-4a=6a-4
2(3a-2)
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