Question

If x + 2a is a factor of x5 – 4a^2x^2
+ 2x + 2a + 3, find a.

Answer 1

Answer:

$x + 2a = 0 \: is \: \: a \: factor \: \: so \: \: \\ \\ x = - 2a \\ \\ {( - 2a)}^{5} - 4 {a}^{2} {( - 2a)}^{2} + 2( - 2a) + 2a + 3 = 0 \\ \\ - 32 {a}^{5} - 16 {a}^{4} - 4a + 2a + 3 = 0 \\ \\ - 32 {a}^{5} - 16 {a}^{4} - 2a + 3 = 0 \\ \\ a = \frac{1}{2} ........$