Question

if x=2and x=0 are root of the polynomial f(x)=2x^3-5x^2+ax+b,then find the value of a and b

Answer 1

X = 2
2×(2)^3 - 5(2)^2 + 2a +b = 0
2 × 8 - 5 × 4 + 2a + b = 0
16 - 20 + 2a + b = 0
-4 + 2a + b = 0
a + b = 4/2
a + b = 2
So, a = 2 and b = 0
X = 0
2(0)^3 - 5(0)^2 + a×0 + b = 0
0 - 0 + 0 + b = 0
So, a = 0, b = 0
This is the solution of your question. I hope that it will help you.

Answer 2

Put the value of x tht is given then if u take the value nd put the answer wull be
A=2
B=0

Now, if u take x=2 then conclution will be a+b=2-------eq1
Then u'll take x=0 we know tht if we multiple any digit or number with 0 the answer is always zero so at the end of the second case you will find b is equals to zero so if you put the value of B in 1st equation you will find the value of a that is 2