If x+2and x-3 are factors of 2x³+ax²+bx-18find value of a and b
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Answer:
a = 1 , b =-15
Step-by-step explanation:
given 2x^3 +ax^2+bx-18=0--(1)
x+2 is root then x=-2in equation (1)
2(-2)^3 +a(-2)^2 +b(-2) -18=0
4a-2b-34=0
2a-b-17=0---(2)
(x-3) is root then x=3 in equation (1)
2(3)^3 +a(3)^2 +b(3)-18=0
9a+3b+36=0
3a+b+12=0---(3)
by solving equation (2) and (3) we get
5a -5=0
a=1 ,
substitute 'a' value in equation (2)
b = -15
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