Question

if x=2and x=3are roots of equation 3x²-2kx+2m=0 find the vaule of k and m

Answer 1

Sum of roots = 2k/3
5 = 2k/3 

k = 15/2

Product of roots = 2m/3
6 = 2m/3

m = 9

Answer 2

put x=2 and x=3 individually and get the equation in terms of m and k
x=2
3(2)^2 -2k(2) + 2m =0
2k-m=6....(1)

x=3
3(3)^2 -2k(3) +2m=0
6k-2m= 27......(2)
eq(2) - 2×eq(1)
2k = 15
k= 15/2
put in equation 1
m= 9