If x-2and2x-1 are factors of ax^2+5x+b show that a-b=0
Answers
Step-by-step explanation:
Given : x - 2 and 2x - 1 are the factors of the polynomial given below :
f(x) = ax² + 5x + b
If (x - 2) is a factor, then
x - 2 = 0
x = 2
So, f(2) = 0
f(2) = a(2)² + 5(2) + b
0 = 4a + 10 + b
4a + b = - 10 ...(i)
If (2x - 1) is a factor, then
2x - 1 = 0
x = 1/2
So, f(1/2) = 0
f(1/2) = a(1/2)² + 5(1/2) + b
0 = a/4 + 5/2 + b
0 = (a + 10 + 4b)/4
a + 4b = - 10 ...(ii)
Multiplying (ii) by 4, we get
4(a + 4b) = 4(- 10)
4a + 16b = - 40 ...(iii)
Subtracting (i) and (iii), we get
→ - 15b = 30
→ b = - 2
Put this value in (ii), we get
→ a + 4(- 2) = - 10
→ a + (-8) = - 10
→ a = - 10 + 8
→ a = - 2
Now,
a - b = - 2 - (- 2)
= - 2 + 2
= 0
Hence, proved !!