if x=2andy=1 is a unique solution of the system x-y-1=0 and x+ky-5=0 then k=
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Answered by
2
k= 3
becouse, x=2,y=1
2+kx1-5=0
2+k=5
k=5-2
k= 3
becouse, x=2,y=1
2+kx1-5=0
2+k=5
k=5-2
k= 3
Answered by
0
x+ky-5=0 now substitute so equation will be 2+k*1-5=0 take 5 the other side so equation will be 2+k=5 now take 2 to the other side so equation will be k=5-2 ,k=3 . I hope my answer satisfies you
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