Question

if x=2cost-cos2t y=2sint -sin2t then dy/dx=​

Answer 1

hope it helps you ........

Answer 2

given x=2cost-cos2t y=2sint -sin2t

to find: dy/dx

• x= 2cost-cos2t    

        dx/dt = 2(-sint) - (-sin2t)(2)    

        =   ( -2sint + 2sin2t )

             (by normal differentiation process)

now,

• y = 2sint - sin2t

       dy/dt = 2(cost) - (cos2t)(2)    

       =   ( 2cost-2cos2t )

            (by normal differentiation process)

so,

• dy/dx = dy/dt * dt/dx   

                =    2(cost-cos2t)/2(-sint+sin2t)

                       (cancelling 2 from numerator and denominator)

• dy/dx = (cost- cos2t)/(sin2t-sint)