Math, asked by rakshayaragavi, 7 months ago

if x+2is a zero of the polynomial p(x)=2x⁴+7x³+kx+10​

Answers

Answered by madhurivnt
1

Answer:

k = -7

Step-by-step explanation:

Let, p(x) = 2x^4 + 7x^3 + kx + 10

APQ, x+2 is a zero of p(x).

So, x+2 = 0

x = -2

Putting this value of x in the equation p(x), we get —

» 2(-2)^4 + 7(-2)^3 + k(-2) + 10

» 32 + (-56) -2k + 10

» -14 - 2k = 0 (as x = -2 was a zero)

» -2k = 14

» k = -7

Hope it helps !

Answered by NegiBhi
0

Ans equation is p(x)=2x⁴+7x³-7x+10

Step-by-step explanation:

if x+2 is a zero of the polynomial

p(x)=2x⁴+7x³+kx+10 ......... eq1

# it mean if we put x=-2 in place of x in eq1

2x⁴+7x³+kx+10 =0

» 2.2⁴-7.2³+k.2+10=0

» 2.16 - 7.8 + 2k + 10 = 0

» 32 - 56 -2k + 10 = 0

» 2k + 42 - 56 = 0

» - 2k = 14

» k = -7

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