if X+2is G.C.D of the polynomials.(x-4)(2x(2)+x-a) and (X+1)(2x+bx-12),then value of (5a-6b) is
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Step-by-step explanation:
If (x+2) is HCF of
P(x)=(x-4)(2x^2+x-a) then
P(-2)=0
(2–4)(2×4–2-a)=0
(6-a)=0
a=6
If (x+2) is HCF of
G(x)=(x+1)(2x^2-bx-12) then
G(-2)=0
(-2+1){2×4-b×(-2)-12}=0
-4–2b=0
b=-2
5a-6b=5×6–6×(-2)=30+12=42
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