if x = 2k+1 and y = k is a solutiom of the equatin 5x + 3y - 7 = 0, find k
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Answered by
30
◐ Given ◐
- x = 2k + 1
- y = k
- is a solution of the equation 5x + 3y - 7 = 0
◐ To find ◐
- Value of k
◐ Solution ◐
- 5x + 3y - 7 = 0
☯ Substitute the value of x and y
- 5(2k + 1) + 3(k) - 7 = 0
- 10k + 5 + 3k - 7 = 0
- 13k + 5 - 7 = 0
- 13k - 2 = 0
- 13k = 2
- k = 2/13
∅ The value of k is ²⁄₁₃
Answered by
3
◐ Given ◐
x = 2k + 1
y = k
is a solution of the equation 5x + 3y - 7 = 0
◐ To find ◐
Value of k
◐ Solution ◐
5x + 3y - 7 = 0
☯ Substitute the value of x and y
5(2k + 1) + 3(k) - 7 = 0
10k + 5 + 3k - 7 = 0
13k + 5 - 7 = 0
13k - 2 = 0
13k = 2
k = 2/13
∅ The value of k is ²⁄₁₃
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