if x=2k+1 and y=k is a solution of equation 5x+3y-7=0 , find the value of 'k'.
Answers
Answered by
7
Answer:
k=2/13
Step-by-step explanation:
given
x=2k+1 and y=k
now putting the value of x and y in
5(2k+1)+3k-7=0
10k+5+3k-7=0
13k-2=O
13k=2
k=2/13
Answered by
0
◐ Given ◐
x = 2k + 1
y = k
is a solution of the equation 5x + 3y - 7 = 0
◐ To find ◐
Value of k
◐ Solution ◐
5x + 3y - 7 = 0
☯ Substitute the value of x and y
5(2k + 1) + 3(k) - 7 = 0
10k + 5 + 3k - 7 = 0
13k + 5 - 7 = 0
13k - 2 = 0
13k = 2
k = 2/13
∅ The value of k is ²⁄₁₃
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