Math, asked by jwala0914, 11 months ago

if x=2k+1 and y=k is a solution of equation 5x+3y-7=0 , find the value of 'k'.​

Answers

Answered by sandeep12399
7

Answer:

k=2/13

Step-by-step explanation:

given

x=2k+1 and y=k

now putting the value of x and y in

5(2k+1)+3k-7=0

10k+5+3k-7=0

13k-2=O

13k=2

k=2/13

Answered by Anonymous
0

◐ Given ◐

x = 2k + 1

y = k

is a solution of the equation 5x + 3y - 7 = 0

◐ To find ◐

Value of k

◐ Solution ◐

5x + 3y - 7 = 0

☯ Substitute the value of x and y

5(2k + 1) + 3(k) - 7 = 0

10k + 5 + 3k - 7 = 0

13k + 5 - 7 = 0

13k - 2 = 0

13k = 2

k = 2/13

∅ The value of k is ²⁄₁₃

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