If x+2k is a factor of f(x)=x5-4k2x3+2x+2k+3,find k
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Let p(x) = x5 − 4k2x3 + 2x + 2k + 3
Given (x + 2k) is a factor of p(x)
Hence p(−2k) = 0 by remainder theorem
Put x = −2k in p(x)
p(−2k) = (−2k)5 − 4k2(−2k)3 + 2(−2k) + 2k + 3
0 = −32k5 − 4k2(−8k3) − 4k + 2k + 3
⇒ −32k5 + 32k5 − 2k + 3 = 0
⇒ − 2k + 3 = 0
⇒ 2k = 3
∴ k = (3/2)
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