Question

if x = 2t+1 and y=(2t+1)^2 find dy/dx

can you solve it plz?​

Answer 1

Answer:

Find dy/dx, when x = 2t/(1 + t2) and y = (1 - t2)/(1 + t2

Answer 2

Given- x=2t+1

y=(2t+1)²

To find- dy/dx

= y/x

= (2t+1)(2t+1)/2t+1

= 2t+1

=x

dy/dx= x= 2t+1

Hope it helps you.

Please mark me brainliest.